PREMIUM REVISION NOTES

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Curriculum: Irish Leaving Certificate (ILC)

Level: Ordinary Level (OL)

Subject: Chemistry

Chapter 4: Volumetric Analysis

Status: Complete Syllabus-Aligned Chapter

Prepared By: ExamsLogic Academic Team

Chapter 4 Complete: Volumetric Analysis

This complete chapter combines concentration, standard solutions, acids and bases, titration technique, acid-base titration calculations, and all three required Ordinary Level practicals for Chapter 4.

Syllabus Focus: The Ordinary Level core for this chapter is concentration of solutions, acids and bases, volumetric analysis, and the mandatory experiments 4.1, 4.2 and 4.2A.
ExamsLogic strategy: Learn this chapter in three layers: definitions → technique → calculations. Students usually lose marks on the middle layer, not the maths.

Table of Contents

1. Key words and volume conversion 2. Concentration in mol/L and g/L 3. Percentage concentration and colour intensity 4. Primary standards and standard solutions 5. Acids, bases, salts and neutralisation 6. Arrhenius theory and household examples 7. Volumetric apparatus and correct technique 8. Indicators, titres and concordant results 9. Acid-base titration calculations 10. Mandatory Experiment 4.1 11. Mandatory Experiment 4.2 12. Mandatory Experiment 4.2A 13. Extension: redox titration note 14. Final exam review

1. Key Words and Volume Conversion

TermMeaningExample
SolutionA mixture formed when a solute dissolves in a solvent.Salt water
SoluteThe substance that dissolves.Sodium chloride
SolventThe liquid that does the dissolving.Water
ConcentrationThe amount of solute dissolved in a given volume of solution.0.100 mol/L HCl
Standard solutionA solution of accurately known concentration.0.0500 mol/L sodium carbonate
TitreThe volume delivered from the burette during a titration.24.30 cm³
1000 cm³ = 1 L = 1 dm³
Volume in L (or dm³) = cm³ ÷ 1000
cm³ lab reading ÷ 1000 L or dm³ calculation unit
Always check the unit before substituting into a concentration formula.
Worked example: 25.0 cm³ = 25.0 ÷ 1000 = 0.0250 dm³.
Common mistake: Using 25 instead of 0.025 in a molarity formula makes the answer 1000 times too large.

2. Concentration in mol/L and g/L

2.1 Concentration in mol/L

Concentration = moles ÷ volume
c = n ÷ V

At Ordinary Level, the volume must be in litres or dm³.

Worked example 1:
0.20 mol NaCl is dissolved to make 500 cm³ of solution.
V = 0.500 dm³
c = n ÷ V = 0.20 ÷ 0.500 = 0.40 mol/L
Worked example 2:
How many moles are present in 250 cm³ of 0.10 mol/L HCl?
V = 0.250 dm³
n = c × V = 0.10 × 0.250 = 0.025 mol

2.2 Concentration in g/L

Concentration (g/L) = mass (g) ÷ volume (L)
Worked example:
5.0 g sodium chloride is dissolved to make 250 cm³ of solution.
V = 0.250 L
Concentration = 5.0 ÷ 0.250 = 20 g/L

2.3 Converting between g/L and mol/L

Concentration (mol/L) = concentration (g/L) ÷ molar mass
Worked example:
A glucose solution has concentration 18 g/L. Glucose has molar mass 180 g/mol.
18 ÷ 180 = 0.10 mol/L
Examiner tip: If the question gives grams and asks for mol/L, first convert to g/L or to moles. Do not jump straight to the answer.

3. Percentage Concentration and Colour Intensity

3.1 Percentage concentration

TypeMeaningExample
% w/vgrams of solute in 100 cm³ of solution5% w/v glucose
% v/vcm³ of liquid solute in 100 cm³ of solution12% v/v wine / 70% v/v ethanol
% w/wgrams of solute in 100 g of mixture10% w/w ointment
Worked example:
A solution is labelled 2% w/v sodium chloride. How much sodium chloride is present in 250 cm³?
2 g in 100 cm³, so in 250 cm³ there is 2 × 2.5 = 5 g.

3.2 Colour intensity as a function of concentration

For a coloured solution, a higher concentration usually means a darker or more intense colour. When the solution is diluted, the colour becomes paler.

Colour Intensity and Concentration dilute medium concentrated More concentrated coloured solutions usually appear darker.
This is only a simple OL treatment, but it is a required syllabus idea.
Exam link: If two coloured solutions are made from the same substance and one looks darker, the darker one is usually more concentrated.
Common mistake: Do not confuse colour intensity with a different substance. The substance may be the same, only the concentration changes.

4. Primary Standards and Standard Solutions

4.1 Primary standards

A primary standard is a pure, stable substance that can be weighed accurately and used to prepare a solution of accurately known concentration.

PropertyWhy it matters
Very pureThe measured mass must represent the substance only.
Stable in airIt should not react easily with oxygen, water vapour or carbon dioxide.
Soluble in waterIt must dissolve to make the solution.
Not hygroscopicIt must not absorb water from the air.
Fairly high molar massThis reduces percentage weighing error.
Examiner trap: Sodium hydroxide is not a good primary standard because it absorbs water and carbon dioxide from the air.

4.2 Standard solutions

A standard solution has an accurately known concentration. It is often made from a primary standard and then used in a titration.

1. Weigh solid accurately 2. Dissolve in deionised water 3. Transfer to volumetric flask 4. Make up to the mark Volumetric flask bottom of meniscus on the calibration mark
A volumetric flask is used because it measures one accurate final volume.
  1. Accurately weigh the required mass of solid.
  2. Dissolve it in a beaker using deionised water.
  3. Transfer the solution to a volumetric flask with a funnel.
  4. Rinse the beaker and funnel into the flask so no solute is lost.
  5. Add water until the bottom of the meniscus is on the calibration mark.
  6. Stopper and invert the flask several times to mix thoroughly.
Common mistake: Forgetting to rinse the beaker and funnel leaves some solute behind and makes the final solution too dilute.

5. Acids, Bases, Salts and Neutralisation

5.1 Acids, bases and salts

TermSimple OL meaningExample
AcidA substance that forms hydrogen ions in water.Hydrochloric acid, vinegar
BaseA substance that reacts with an acid.Sodium hydroxide, magnesium oxide
AlkaliA soluble base.Sodium hydroxide solution
SaltA compound formed when the H⁺ of an acid is replaced by a metal or ammonium ion.Sodium chloride

5.2 Neutralisation

Neutralisation is the reaction between an acid and a base to produce a salt and usually water.

acid + base → salt + water
HCl + NaOH → NaCl + H₂O
Acid provides H⁺ in water + Base reacts with acid Salt Water
This is one of the key ideas behind acid-base titrations.
Example: HCl + NaOH → NaCl + H₂O is a neutralisation reaction because an acid reacts with a base to form a salt and water.

6. Arrhenius Theory and Household Examples

6.1 Arrhenius theory

Arrhenius acid: produces H⁺ in water
Arrhenius base: produces OH⁻ in water

Examples:

Examiner trap: At OL for this chapter, stick to the Arrhenius theory. Do not drift into Higher Level ideas unless the teacher asks.

6.2 Household acids and bases

Two household acids

  • Vinegar (contains ethanoic acid)
  • Lemon juice (contains citric acid)

Two household bases

  • Baking soda / sodium hydrogencarbonate
  • Household ammonia / cleaning alkali

6.3 Everyday examples of neutralisation

ExampleWhat is happening?
Lime used in agricultureAcidic soil is neutralised so crops grow better.
Stomach powders / antacidsExcess stomach acid is neutralised.
Examiner secret: When asked for an everyday neutralisation example, state both the substances and the purpose.

7. Volumetric Apparatus and Correct Titrimetric Procedure

7.1 Apparatus used in volumetric analysis

ApparatusUse
Volumetric flaskMaking a standard solution to one exact final volume.
PipetteMeasuring one fixed accurate volume into the conical flask.
Pipette fillerSafe filling of pipettes.
BuretteDelivering a variable measured volume during titration.
Conical flaskHolding the reacting solution during titration.
White tileMakes the indicator colour change easier to see.

7.2 Correct titrimetric procedure

  1. Rinse the burette with the solution it will contain.
  2. Fill the burette and remove any air bubble from the tip.
  3. Record the initial burette reading at eye level.
  4. Rinse the pipette with the solution it will measure.
  5. Use the pipette to transfer a fixed volume into the conical flask.
  6. Add a few drops of suitable indicator.
  7. Run the burette solution into the flask while swirling.
  8. Near the end-point, add the solution drop by drop.
  9. Record the final burette reading.
  10. Repeat until concordant titres are obtained.
Burette known solution tap Conical flask fixed volume by pipette + indicator End-point permanent colour change
The burette delivers one solution into the conical flask until the end-point is reached.
Examiner tip: Questions on practical errors often reward answers like rinse the burette, read the meniscus at eye level, use a white tile, and swirl during titration.

8. Indicators, Titres and Concordant Results

8.1 Indicators

IndicatorAcid colourAlkali colourCommon use
Methyl orangeRedYellowStrong acid + weak base, or strong acid + strong base
PhenolphthaleinColourlessPinkWeak acid + strong base, or strong acid + strong base

8.2 Titre and average titre

Titre = final reading − initial reading
Average titre = mean of concordant titres only
Finding the Titre 0.50 cm³ Initial 24.80 cm³ Final Titre 24.80 − 0.50 = 24.30 cm³
The titre is not the final reading on its own.
Concordant titres: 24.80 cm³, 24.85 cm³, 24.90 cm³ are concordant because they are close together.
Common mistake: Do not average the rough titre with the accurate titres.

9. Acid-Base Titration Calculations

Most Ordinary Level volumetric problems are solved with the same structure:

  1. Convert volume to dm³.
  2. Find moles of the known solution.
  3. Use the balanced equation ratio.
  4. Find the unknown concentration.
moles = concentration × volume
\( \frac{M_1V_1}{n_1} = \frac{M_2V_2}{n_2} \)
Formula method: In OL exams, balanced equations are given. Your job is to use the correct mole ratio.

9.1 Worked example: 1:1 reaction

Question: 25.0 cm³ of sodium hydroxide is neutralised by 20.0 cm³ of 0.100 mol/L HCl. Find the concentration of NaOH.

Equation: HCl + NaOH → NaCl + H₂O
Ratio = 1:1

Moles HCl = 0.100 × 0.0200 = 0.00200 mol
Therefore moles NaOH = 0.00200 mol
Volume NaOH = 0.0250 dm³
Concentration NaOH = 0.00200 ÷ 0.0250 = 0.0800 mol/L

9.2 Worked example: 2:1 reaction

Question: 25.0 cm³ sodium carbonate reacts with 30.0 cm³ of 0.100 mol/L HCl. Find the concentration of sodium carbonate.

Equation: Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂
Ratio Na₂CO₃ : HCl = 1 : 2

Moles HCl = 0.100 × 0.0300 = 0.00300 mol
Moles Na₂CO₃ = 0.00300 ÷ 2 = 0.00150 mol
Concentration Na₂CO₃ = 0.00150 ÷ 0.0250 = 0.0600 mol/L
Examiner trap: Carbonates often react with acids in a 1:2 ratio. If you forget the 2 in front of HCl, your answer will be wrong.

10. Mandatory Experiment 4.1

Preparation of a Standard Solution of Sodium Carbonate

Aim

To prepare a standard solution of sodium carbonate of accurately known concentration.

Primary standard used

Sodium carbonate is suitable because it is pure, stable and can be weighed accurately.

Main skill

Accurate weighing, dissolving, transfer and making up to the mark in a volumetric flask.

Apparatus and chemicals

Method

  1. Accurately weigh the required mass of sodium carbonate.
  2. Dissolve it in a beaker using a small volume of deionised water.
  3. Transfer the solution through a funnel into a volumetric flask.
  4. Rinse the beaker, rod and funnel into the flask.
  5. Make the solution up to the calibration mark with deionised water.
  6. Stopper and invert several times to mix.
Why rinse? Rinsing ensures that all the sodium carbonate reaches the volumetric flask, so the concentration is accurate.
Practical error: If the solution is made above the calibration mark, the concentration will be too low.

Result statement

A standard sodium carbonate solution of known concentration is prepared for use in the next mandatory titration.

11. Mandatory Experiment 4.2

Standardisation of Hydrochloric Acid Using Standard Sodium Carbonate

Aim

To determine the concentration of hydrochloric acid by titrating it against a standard sodium carbonate solution.

Balanced equation

Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂

Apparatus and chemicals

Method

  1. Rinse the burette with hydrochloric acid and fill it.
  2. Rinse the pipette with standard sodium carbonate solution.
  3. Pipette 25.0 cm³ sodium carbonate into a conical flask.
  4. Add a few drops of methyl orange.
  5. Titrate with hydrochloric acid until the indicator changes permanently.
  6. Repeat to obtain concordant titres.
Indicator choice: Methyl orange is suitable because the titration of sodium carbonate with hydrochloric acid ends in the acidic pH range.

Typical calculation structure

If 25.0 cm³ of 0.0500 mol/L Na₂CO₃ requires 20.0 cm³ HCl:

Moles Na₂CO₃ = 0.0500 × 0.0250 = 0.00125 mol
Ratio Na₂CO₃ : HCl = 1 : 2
Moles HCl = 0.00250 mol
Concentration HCl = 0.00250 ÷ 0.0200 = 0.125 mol/L
Common mistake: Forgetting the 2 in the balanced equation gives an HCl concentration that is only half-right.

12. Mandatory Experiment 4.2A

Hydrochloric Acid / Sodium Hydroxide Titration and Making Sodium Chloride

Aim

To titrate hydrochloric acid with sodium hydroxide and use the result to prepare sodium chloride.

Balanced equation

HCl + NaOH → NaCl + H₂O

Part A: Titration

  1. Pipette a fixed volume of sodium hydroxide into the conical flask.
  2. Add a few drops of indicator.
  3. Titrate with hydrochloric acid from the burette to the end-point.
  4. Repeat until concordant titres are obtained.

Part B: Making sodium chloride

  1. Repeat the titration using the exact same measured volumes but without indicator.
  2. When neutralisation is complete, the flask contains sodium chloride solution and water.
  3. Transfer the neutral solution to an evaporating dish.
  4. Evaporate gently to concentrate the solution.
  5. Allow crystals of sodium chloride to form.
  6. Filter if needed and dry the crystals.
Important reason: The final salt is prepared without indicator so the product is not contaminated by indicator dye.
Titration find exact neutral volume Repeat without indicator Evaporate to get NaCl crystals
This practical links titration technique to salt preparation.
Common mistake: Students sometimes try to evaporate the solution from the indicator titration. That would contaminate the sodium chloride.

13. Extension: Redox Titration Note

Extension only: Some of your original part files included iodine-thiosulfate titrations. That is useful enrichment, but the Ordinary Level Chapter 4 core is built around acid-base titrations, not redox titrations.

A redox titration is still based on measured volumes and mole ratios, but the reacting substances undergo oxidation and reduction. One common example is:

I₂ + 2S₂O₃²⁻ → 2I⁻ + S₄O₆²⁻

In that reaction, 1 mole of iodine reacts with 2 moles of thiosulfate. Starch is used as an indicator because it gives a strong blue-black colour with iodine.

Why keep this section? It is good extension material and useful for stronger students, but it should be treated as enrichment beside the OL acid-base core.

14. Final Exam Review

14.1 One-page checklist

14.2 Quick-fire worked questions

Q1. Convert 32.5 cm³ to dm³.
Answer: 0.0325 dm³
Q2. Find the concentration of a solution made by dissolving 0.050 mol in 250 cm³.
Answer: 0.050 ÷ 0.250 = 0.20 mol/L
Q3. What is the titre if the burette goes from 1.20 cm³ to 25.80 cm³?
Answer: 24.60 cm³
Q4. Give one everyday example of neutralisation.
Answer: Antacids neutralise excess stomach acid.

14.3 Examiner tips, traps and common mistakes

Examiner tip: Always write the balanced equation before the titration calculation if it is relevant to the ratio.
Examiner tip: Read burette values at eye level and from the bottom of the meniscus.
Examiner trap: A rough titre is for finding the approximate end-point. It is not normally included in the average.
Common mistake: Students often know the chemistry but lose marks because they forget to convert cm³ to dm³.
Common mistake: Students say “acid + alkali makes water only.” The full answer is usually salt + water.

14.4 Chapter verdict

If you can do these three things, you are in good shape for Chapter 4:
  1. Prepare a standard solution accurately.
  2. Describe a full titration method clearly.
  3. Carry out the mole-ratio calculation without unit mistakes.

Chapter 4 Complete

You have now completed Chapter 4: Volumetric Analysis for ILC Chemistry Ordinary Level.

Next chapter: Fuels and Heats of Reaction.